t^2=6.2t

Solution for t^2=6.2t equation:

t^2=6.2t

We move all terms to the left:

t^2-(6.2t)=0

We add all the numbers together, and all the variables

t^2-(+6.2t)=0

We get rid of parentheses

t^2-6.2t=0

a = 1; b = -6.2; c = 0;
Δ = b2-4ac
Δ = -6.22-4·1·0
Δ = 38.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6.2)-\sqrt{38.44}}{2*1}=\frac{6.2-\sqrt{38.44}}{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6.2)+\sqrt{38.44}}{2*1}=\frac{6.2+\sqrt{38.44}}{2}
$